-150x^2-525x+6000=0

Solution for -150x^2-525x+6000=0 equation:

-150x^2-525x+6000=0

a = -150; b = -525; c = +6000;
Δ = b2-4ac
Δ = -5252-4·(-150)·6000
Δ = 3875625
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{3875625}=\sqrt{5625*689}=\sqrt{5625}*\sqrt{689}=75\sqrt{689}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-525)-75\sqrt{689}}{2*-150}=\frac{525-75\sqrt{689}}{-300}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-525)+75\sqrt{689}}{2*-150}=\frac{525+75\sqrt{689}}{-300}
$